![]() The Fluid Force on a Vertical Surface Suppose a flat surface is submerged vertically in a fluid of weight density w and the submerged portion of the surface extends from x a to x b along the vertical x -axis, whose positive direction is taken as downward. † † margin: y y x - 2 - 1 1 2 - 2 - 1 1 2 50 water line not to scale d ( y ) = 50 - y Figure 6.5.8: Measuring the fluid force on an underwater porthole in Example 6.5.4.62. To find the fluid force or pressure on a vertical surface we must use calculus. The truth is that it is not, hence the survival tips mentioned at the beginning of this section. This is counter-intuitive as most assume that the door would be relatively easy to open. Most adults would find it very difficult to apply over 500 lb of force to a car door while seated inside, making the door effectively impossible to open. Using the weight-density of water of 62.4 lb/ft 3, we have the total force as Letting y be the distance from the top of the window to the cross section, we have (5.1.7) F 62.4 ( 4 + y) A 62.4 4 + y 3 y. (The weight-density of water is 62.4 pounds per cubic foot.) lb Trapezoid. Solution We take horizontal cross sections. We adopt the convention that the top of the door is at the surface of the water, both of which are at y = 0. 96 (23 ratings) Transcribed image text: Find the fluid force on the vertical side of the tank, where the dimensions are given in feet. ![]() Its length is 10 / 3 ft and its height is 2.25 ft. SolutionThe car door, as a rectangle, is drawn in Figure 6.5.7. fluid force on the vertical side of the tank, where the dimensions are given in feet.
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